6q(5q+3)=0

Solution for 6q(5q+3)=0 equation:

6q(5q+3)=0

We multiply parentheses

30q^2+18q=0

a = 30; b = 18; c = 0;
Δ = b2-4ac
Δ = 182-4·30·0
Δ = 324
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$q_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$q_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{324}=18$
$q_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(18)-18}{2*30}=\frac{-36}{60}
=-3/5
$
$q_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(18)+18}{2*30}=\frac{0}{60}
=0
$