6q+3(1-q)=1q+4(1-q)

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Solution for 6q+3(1-q)=1q+4(1-q) equation:



6q+3(1-q)=1q+4(1-q)
We move all terms to the left:
6q+3(1-q)-(1q+4(1-q))=0
We add all the numbers together, and all the variables
6q+3(-1q+1)-(1q+4(-1q+1))=0
We multiply parentheses
6q-3q-(1q+4(-1q+1))+3=0
We calculate terms in parentheses: -(1q+4(-1q+1)), so:
1q+4(-1q+1)
We add all the numbers together, and all the variables
q+4(-1q+1)
We multiply parentheses
q-4q+4
We add all the numbers together, and all the variables
-3q+4
Back to the equation:
-(-3q+4)
We add all the numbers together, and all the variables
3q-(-3q+4)+3=0
We get rid of parentheses
3q+3q-4+3=0
We add all the numbers together, and all the variables
6q-1=0
We move all terms containing q to the left, all other terms to the right
6q=1
q=1/6
q=1/6

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