6q-(4q+5)=7-(3q-6)

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Solution for 6q-(4q+5)=7-(3q-6) equation: 



6q-(4q+5)=7-(3q-6)

We move all terms to the left:

6q-(4q+5)-(7-(3q-6))=0

We get rid of parentheses

6q-4q-(7-(3q-6))-5=0



We calculate terms in parentheses: -(7-(3q-6)), so:

7-(3q-6)

determiningTheFunctionDomain
-(3q-6)+7

We get rid of parentheses

-3q+6+7

We add all the numbers together, and all the variables

-3q+13

Back to the equation:

-(-3q+13)



We add all the numbers together, and all the variables

2q-(-3q+13)-5=0

We get rid of parentheses

2q+3q-13-5=0

We add all the numbers together, and all the variables

5q-18=0

We move all terms containing q to the left, all other terms to the right

5q=18

q=18/5

q=3+3/5

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