6q-(5q+5)=-8-2(q+12)

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Solution for 6q-(5q+5)=-8-2(q+12) equation: 



6q-(5q+5)=-8-2(q+12)

We move all terms to the left:

6q-(5q+5)-(-8-2(q+12))=0

We get rid of parentheses

6q-5q-(-8-2(q+12))-5=0



We calculate terms in parentheses: -(-8-2(q+12)), so:

-8-2(q+12)

determiningTheFunctionDomain
-2(q+12)-8

We multiply parentheses

-2q-24-8

We add all the numbers together, and all the variables

-2q-32

Back to the equation:

-(-2q-32)



We add all the numbers together, and all the variables

q-(-2q-32)-5=0

We get rid of parentheses

q+2q+32-5=0

We add all the numbers together, and all the variables

3q+27=0

We move all terms containing q to the left, all other terms to the right

3q=-27

q=-27/3

q=-9

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