6q-348=6(2-5q)-4q

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Solution for 6q-348=6(2-5q)-4q equation: 



6q-348=6(2-5q)-4q

We move all terms to the left:

6q-348-(6(2-5q)-4q)=0

We add all the numbers together, and all the variables

6q-(6(-5q+2)-4q)-348=0



We calculate terms in parentheses: -(6(-5q+2)-4q), so:

6(-5q+2)-4q

We add all the numbers together, and all the variables

-4q+6(-5q+2)

We multiply parentheses

-4q-30q+12

We add all the numbers together, and all the variables

-34q+12

Back to the equation:

-(-34q+12)



We get rid of parentheses

6q+34q-12-348=0

We add all the numbers together, and all the variables

40q-360=0

We move all terms containing q to the left, all other terms to the right

40q=360

q=360/40

q=9

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