6r-28=4(1+3r)-2r

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Solution for 6r-28=4(1+3r)-2r equation:



6r-28=4(1+3r)-2r
We move all terms to the left:
6r-28-(4(1+3r)-2r)=0
We add all the numbers together, and all the variables
6r-(4(3r+1)-2r)-28=0
We calculate terms in parentheses: -(4(3r+1)-2r), so:
4(3r+1)-2r
We add all the numbers together, and all the variables
-2r+4(3r+1)
We multiply parentheses
-2r+12r+4
We add all the numbers together, and all the variables
10r+4
Back to the equation:
-(10r+4)
We get rid of parentheses
6r-10r-4-28=0
We add all the numbers together, and all the variables
-4r-32=0
We move all terms containing r to the left, all other terms to the right
-4r=32
r=32/-4
r=-8

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