6r-3(2+r)=-(r+2)

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Solution for 6r-3(2+r)=-(r+2) equation: 



6r-3(2+r)=-(r+2)

We move all terms to the left:

6r-3(2+r)-(-(r+2))=0

We add all the numbers together, and all the variables

6r-3(r+2)-(-(r+2))=0

We multiply parentheses

6r-3r-(-(r+2))-6=0



We calculate terms in parentheses: -(-(r+2)), so:

-(r+2)

We get rid of parentheses

-r-2

We add all the numbers together, and all the variables

-1r-2

Back to the equation:

-(-1r-2)



We add all the numbers together, and all the variables

3r-(-1r-2)-6=0

We get rid of parentheses

3r+1r+2-6=0

We add all the numbers together, and all the variables

4r-4=0

We move all terms containing r to the left, all other terms to the right

4r=4

r=4/4

r=1

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