6r-3-r=-7(r+5)+8(2r-1)

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Solution for 6r-3-r=-7(r+5)+8(2r-1) equation: 



6r-3-r=-7(r+5)+8(2r-1)

We move all terms to the left:

6r-3-r-(-7(r+5)+8(2r-1))=0

We add all the numbers together, and all the variables

5r-(-7(r+5)+8(2r-1))-3=0



We calculate terms in parentheses: -(-7(r+5)+8(2r-1)), so:

-7(r+5)+8(2r-1)

We multiply parentheses

-7r+16r-35-8

We add all the numbers together, and all the variables

9r-43

Back to the equation:

-(9r-43)



We get rid of parentheses

5r-9r+43-3=0

We add all the numbers together, and all the variables

-4r+40=0

We move all terms containing r to the left, all other terms to the right

-4r=-40

r=-40/-4

r=+10

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