6r2-10r-136=0

Solution for 6r2-10r-136=0 equation:

6r^2-10r-136=0

a = 6; b = -10; c = -136;
Δ = b2-4ac
Δ = -102-4·6·(-136)
Δ = 3364
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$r_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$r_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{3364}=58$
$r_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-10)-58}{2*6}=\frac{-48}{12}
=-4
$
$r_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-10)+58}{2*6}=\frac{68}{12}
=5+2/3
$