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6r^2=12(3.14)
We move all terms to the left:
6r^2-(12(3.14))=0
We add all the numbers together, and all the variables
6r^2-37.68=0
a = 6; b = 0; c = -37.68;
Δ = b2-4ac
Δ = 02-4·6·(-37.68)
Δ = 904.32
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$r_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$r_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$r_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-\sqrt{904.32}}{2*6}=\frac{0-\sqrt{904.32}}{12} =-\frac{\sqrt{}}{12} $$r_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+\sqrt{904.32}}{2*6}=\frac{0+\sqrt{904.32}}{12} =\frac{\sqrt{}}{12} $
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