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6r^2=43.96
We move all terms to the left:
6r^2-(43.96)=0
We add all the numbers together, and all the variables
6r^2-43.96=0
a = 6; b = 0; c = -43.96;
Δ = b2-4ac
Δ = 02-4·6·(-43.96)
Δ = 1055.04
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$r_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$r_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$r_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-\sqrt{1055.04}}{2*6}=\frac{0-\sqrt{1055.04}}{12} =-\frac{\sqrt{}}{12} $$r_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+\sqrt{1055.04}}{2*6}=\frac{0+\sqrt{1055.04}}{12} =\frac{\sqrt{}}{12} $
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