6s+2(2+4)=2(s-2)-4

Solution for 6s+2(2+4)=2(s-2)-4 equation:

6s+2(2+4)=2(s-2)-4

We move all terms to the left:

6s+2(2+4)-(2(s-2)-4)=0

We add all the numbers together, and all the variables

6s-(2(s-2)-4)+26=0


We calculate terms in parentheses: -(2(s-2)-4), so:

2(s-2)-4

We multiply parentheses

2s-4-4

We add all the numbers together, and all the variables

2s-8

Back to the equation:

-(2s-8)


We get rid of parentheses

6s-2s+8+26=0

We add all the numbers together, and all the variables

4s+34=0

We move all terms containing s to the left, all other terms to the right

4s=-34

s=-34/4

s=-8+1/2