6s-4=8(2+1/2s)

Solution for 6s-4=8(2+1/2s) equation:

6s-4=8(2+1/2s)

We move all terms to the left:

6s-4-(8(2+1/2s))=0


Domain of the equation: 2s))!=0

s!=0/1

s!=0

s∈R


We add all the numbers together, and all the variables

6s-(8(1/2s+2))-4=0

We multiply all the terms by the denominator


6s*2s-4*2s+2))-(8(1+2))=0

We add all the numbers together, and all the variables

6s*2s-4*2s+2))-(83)=0

We add all the numbers together, and all the variables

6s*2s-4*2s=0

Wy multiply elements

12s^2-8s=0

a = 12; b = -8; c = 0;
Δ = b2-4ac
Δ = -82-4·12·0
Δ = 64
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$s_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$s_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{64}=8$
$s_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-8)-8}{2*12}=\frac{0}{24}
=0
$
$s_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-8)+8}{2*12}=\frac{16}{24}
=2/3
$