6s-4=8(2+4/1s)

Solution for 6s-4=8(2+4/1s) equation:

6s-4=8(2+4/1s)

We move all terms to the left:

6s-4-(8(2+4/1s))=0


Domain of the equation: 1s))!=0

s!=0/1

s!=0

s∈R


We add all the numbers together, and all the variables

6s-(8(4/1s+2))-4=0

We multiply all the terms by the denominator


6s*1s-4*1s+2))-(8(4+2))=0

We add all the numbers together, and all the variables

6s*1s-4*1s+2))-(86)=0

We add all the numbers together, and all the variables

6s*1s-4*1s=0

Wy multiply elements

6s^2-4s=0

a = 6; b = -4; c = 0;
Δ = b2-4ac
Δ = -42-4·6·0
Δ = 16
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$s_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$s_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{16}=4$
$s_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-4)-4}{2*6}=\frac{0}{12}
=0
$
$s_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-4)+4}{2*6}=\frac{8}{12}
=2/3
$