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6s^2+17s=0
a = 6; b = 17; c = 0;
Δ = b2-4ac
Δ = 172-4·6·0
Δ = 289
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$s_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$s_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{289}=17$$s_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(17)-17}{2*6}=\frac{-34}{12} =-2+5/6 $$s_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(17)+17}{2*6}=\frac{0}{12} =0 $
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