6t+(2t-4)/3=-2

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Solution for 6t+(2t-4)/3=-2 equation: 



6t+(2t-4)/3=-2

We move all terms to the left:

6t+(2t-4)/3-(-2)=0

We add all the numbers together, and all the variables

6t+(2t-4)/3+2=0

We multiply all the terms by the denominator


6t*3+(2t-4)+2*3=0

We add all the numbers together, and all the variables

6t*3+(2t-4)+6=0

Wy multiply elements

18t+(2t-4)+6=0

We get rid of parentheses

18t+2t-4+6=0

We add all the numbers together, and all the variables

20t+2=0

We move all terms containing t to the left, all other terms to the right

20t=-2

t=-2/20

t=-1/10

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