6t+2(4t-3)=6+5(t+3)

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Solution for 6t+2(4t-3)=6+5(t+3) equation: 



6t+2(4t-3)=6+5(t+3)

We move all terms to the left:

6t+2(4t-3)-(6+5(t+3))=0

We multiply parentheses

6t+8t-(6+5(t+3))-6=0



We calculate terms in parentheses: -(6+5(t+3)), so:

6+5(t+3)

determiningTheFunctionDomain
5(t+3)+6

We multiply parentheses

5t+15+6

We add all the numbers together, and all the variables

5t+21

Back to the equation:

-(5t+21)



We add all the numbers together, and all the variables

14t-(5t+21)-6=0

We get rid of parentheses

14t-5t-21-6=0

We add all the numbers together, and all the variables

9t-27=0

We move all terms containing t to the left, all other terms to the right

9t=27

t=27/9

t=3

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