6t+3/9t-7=2t+6/3t-4

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Solution for 6t+3/9t-7=2t+6/3t-4 equation: 



6t+3/9t-7=2t+6/3t-4

We move all terms to the left:

6t+3/9t-7-(2t+6/3t-4)=0



Domain of the equation: 9t!=0

t!=0/9

t!=0

t∈R





Domain of the equation: 3t-4)!=0

t∈R



We get rid of parentheses

6t+3/9t-2t-6/3t+4-7=0

We calculate fractions


6t-2t+9t/27t^2+(-54t)/27t^2+4-7=0

We add all the numbers together, and all the variables

4t+9t/27t^2+(-54t)/27t^2-3=0

We multiply all the terms by the denominator


4t*27t^2+9t+(-54t)-3*27t^2=0

We add all the numbers together, and all the variables

9t+4t*27t^2+(-54t)-3*27t^2=0

Wy multiply elements

108t^3-81t^2+9t+(-54t)=0

We get rid of parentheses

108t^3-81t^2+9t-54t=0

We do not support etpression: t^3

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