6t-(t+4)=2(t+1)

Solution for 6t-(t+4)=2(t+1) equation:

6t-(t+4)=2(t+1)

We move all terms to the left:

6t-(t+4)-(2(t+1))=0

We get rid of parentheses

6t-t-(2(t+1))-4=0


We calculate terms in parentheses: -(2(t+1)), so:

2(t+1)

We multiply parentheses

2t+2

Back to the equation:

-(2t+2)


We add all the numbers together, and all the variables

5t-(2t+2)-4=0

We get rid of parentheses

5t-2t-2-4=0

We add all the numbers together, and all the variables

3t-6=0

We move all terms containing t to the left, all other terms to the right

3t=6

t=6/3

t=2