6t-4=8(2+1/4t)

Solution for 6t-4=8(2+1/4t) equation:

6t-4=8(2+1/4t)

We move all terms to the left:

6t-4-(8(2+1/4t))=0


Domain of the equation: 4t))!=0

t!=0/1

t!=0

t∈R


We add all the numbers together, and all the variables

6t-(8(1/4t+2))-4=0

We multiply all the terms by the denominator


6t*4t-4*4t+2))-(8(1+2))=0

We add all the numbers together, and all the variables

6t*4t-4*4t+2))-(83)=0

We add all the numbers together, and all the variables

6t*4t-4*4t=0

Wy multiply elements

24t^2-16t=0

a = 24; b = -16; c = 0;
Δ = b2-4ac
Δ = -162-4·24·0
Δ = 256
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{256}=16$
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-16)-16}{2*24}=\frac{0}{48}
=0
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-16)+16}{2*24}=\frac{32}{48}
=2/3
$