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6t^2+7t+2=0
a = 6; b = 7; c = +2;
Δ = b2-4ac
Δ = 72-4·6·2
Δ = 1
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1}=1$$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(7)-1}{2*6}=\frac{-8}{12} =-2/3 $$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(7)+1}{2*6}=\frac{-6}{12} =-1/2 $
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