6t2/5+7t1/5+2=0

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Solution for 6t2/5+7t1/5+2=0 equation: 


t in (-oo:+oo)

(6*t^2)/5+(7*t^1)/5+2 = 0

(6*t^2)/5+(7*t)/5+2 = 0

6/5*t^2+7/5*t+2 = 0

DELTA = (7/5)^2-(6/5*2*4)

DELTA = -191/25

DELTA < 0

t belongs to the empty set

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