6u+32=2(u+2)

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Solution for 6u+32=2(u+2) equation: 



6u+32=2(u+2)

We move all terms to the left:

6u+32-(2(u+2))=0



We calculate terms in parentheses: -(2(u+2)), so:

2(u+2)

We multiply parentheses

2u+4

Back to the equation:

-(2u+4)



We get rid of parentheses

6u-2u-4+32=0

We add all the numbers together, and all the variables

4u+28=0

We move all terms containing u to the left, all other terms to the right

4u=-28

u=-28/4

u=-7

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