6u+36=2(u-2)

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Solution for 6u+36=2(u-2) equation: 



6u+36=2(u-2)

We move all terms to the left:

6u+36-(2(u-2))=0



We calculate terms in parentheses: -(2(u-2)), so:

2(u-2)

We multiply parentheses

2u-4

Back to the equation:

-(2u-4)



We get rid of parentheses

6u-2u+4+36=0

We add all the numbers together, and all the variables

4u+40=0

We move all terms containing u to the left, all other terms to the right

4u=-40

u=-40/4

u=-10

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