6u-2(2u-3)=22-2u

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Solution for 6u-2(2u-3)=22-2u equation: 



6u-2(2u-3)=22-2u

We move all terms to the left:

6u-2(2u-3)-(22-2u)=0

We add all the numbers together, and all the variables

6u-2(2u-3)-(-2u+22)=0

We multiply parentheses

6u-4u-(-2u+22)+6=0

We get rid of parentheses

6u-4u+2u-22+6=0

We add all the numbers together, and all the variables

4u-16=0

We move all terms containing u to the left, all other terms to the right

4u=16

u=16/4

u=4

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