6u-41=3(u+3)-2

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Solution for 6u-41=3(u+3)-2 equation:



6u-41=3(u+3)-2
We move all terms to the left:
6u-41-(3(u+3)-2)=0
We calculate terms in parentheses: -(3(u+3)-2), so:
3(u+3)-2
We multiply parentheses
3u+9-2
We add all the numbers together, and all the variables
3u+7
Back to the equation:
-(3u+7)
We get rid of parentheses
6u-3u-7-41=0
We add all the numbers together, and all the variables
3u-48=0
We move all terms containing u to the left, all other terms to the right
3u=48
u=48/3
u=16

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