6u-8+2(4u+5)=4(u+1)

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Solution for 6u-8+2(4u+5)=4(u+1) equation: 



6u-8+2(4u+5)=4(u+1)

We move all terms to the left:

6u-8+2(4u+5)-(4(u+1))=0

We multiply parentheses

6u+8u-(4(u+1))+10-8=0



We calculate terms in parentheses: -(4(u+1)), so:

4(u+1)

We multiply parentheses

4u+4

Back to the equation:

-(4u+4)



We add all the numbers together, and all the variables

14u-(4u+4)+2=0

We get rid of parentheses

14u-4u-4+2=0

We add all the numbers together, and all the variables

10u-2=0

We move all terms containing u to the left, all other terms to the right

10u=2

u=2/10

u=1/5

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