6v+2(2-4v)=2v+28

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Solution for 6v+2(2-4v)=2v+28 equation: 



6v+2(2-4v)=2v+28

We move all terms to the left:

6v+2(2-4v)-(2v+28)=0

We add all the numbers together, and all the variables

6v+2(-4v+2)-(2v+28)=0

We multiply parentheses

6v-8v-(2v+28)+4=0

We get rid of parentheses

6v-8v-2v-28+4=0

We add all the numbers together, and all the variables

-4v-24=0

We move all terms containing v to the left, all other terms to the right

-4v=24

v=24/-4

v=-6

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