6v+22=2(v-1)

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Solution for 6v+22=2(v-1) equation: 



6v+22=2(v-1)

We move all terms to the left:

6v+22-(2(v-1))=0



We calculate terms in parentheses: -(2(v-1)), so:

2(v-1)

We multiply parentheses

2v-2

Back to the equation:

-(2v-2)



We get rid of parentheses

6v-2v+2+22=0

We add all the numbers together, and all the variables

4v+24=0

We move all terms containing v to the left, all other terms to the right

4v=-24

v=-24/4

v=-6

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