6v+3(5v-4)=(2v+5)

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Solution for 6v+3(5v-4)=(2v+5) equation: 



6v+3(5v-4)=(2v+5)

We move all terms to the left:

6v+3(5v-4)-((2v+5))=0

We multiply parentheses

6v+15v-((2v+5))-12=0



We calculate terms in parentheses: -((2v+5)), so:

(2v+5)

We get rid of parentheses

2v+5

Back to the equation:

-(2v+5)



We add all the numbers together, and all the variables

21v-(2v+5)-12=0

We get rid of parentheses

21v-2v-5-12=0

We add all the numbers together, and all the variables

19v-17=0

We move all terms containing v to the left, all other terms to the right

19v=17

v=17/19

v=17/19

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