6v+3(5v-4)=12(2v+9)

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Solution for 6v+3(5v-4)=12(2v+9) equation:



6v+3(5v-4)=12(2v+9)
We move all terms to the left:
6v+3(5v-4)-(12(2v+9))=0
We multiply parentheses
6v+15v-(12(2v+9))-12=0
We calculate terms in parentheses: -(12(2v+9)), so:
12(2v+9)
We multiply parentheses
24v+108
Back to the equation:
-(24v+108)
We add all the numbers together, and all the variables
21v-(24v+108)-12=0
We get rid of parentheses
21v-24v-108-12=0
We add all the numbers together, and all the variables
-3v-120=0
We move all terms containing v to the left, all other terms to the right
-3v=120
v=120/-3
v=-40

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