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6v-1=3(2-5v)
We move all terms to the left:
6v-1-(3(2-5v))=0
We add all the numbers together, and all the variables
6v-(3(-5v+2))-1=0
We calculate terms in parentheses: -(3(-5v+2)), so:We get rid of parentheses
3(-5v+2)
We multiply parentheses
-15v+6
Back to the equation:
-(-15v+6)
6v+15v-6-1=0
We add all the numbers together, and all the variables
21v-7=0
We move all terms containing v to the left, all other terms to the right
21v=7
v=7/21
v=1/3
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