6v-2+2(4v+1)=-2(v+4)

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Solution for 6v-2+2(4v+1)=-2(v+4) equation: 



6v-2+2(4v+1)=-2(v+4)

We move all terms to the left:

6v-2+2(4v+1)-(-2(v+4))=0

We multiply parentheses

6v+8v-(-2(v+4))+2-2=0



We calculate terms in parentheses: -(-2(v+4)), so:

-2(v+4)

We multiply parentheses

-2v-8

Back to the equation:

-(-2v-8)



We add all the numbers together, and all the variables

14v-(-2v-8)=0

We get rid of parentheses

14v+2v+8=0

We add all the numbers together, and all the variables

16v+8=0

We move all terms containing v to the left, all other terms to the right

16v=-8

v=-8/16

v=-1/2

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