6v-2+2(4v+1)=-2(v+5)

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Solution for 6v-2+2(4v+1)=-2(v+5) equation: 



6v-2+2(4v+1)=-2(v+5)

We move all terms to the left:

6v-2+2(4v+1)-(-2(v+5))=0

We multiply parentheses

6v+8v-(-2(v+5))+2-2=0



We calculate terms in parentheses: -(-2(v+5)), so:

-2(v+5)

We multiply parentheses

-2v-10

Back to the equation:

-(-2v-10)



We add all the numbers together, and all the variables

14v-(-2v-10)=0

We get rid of parentheses

14v+2v+10=0

We add all the numbers together, and all the variables

16v+10=0

We move all terms containing v to the left, all other terms to the right

16v=-10

v=-10/16

v=-5/8

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