6v-8+11=6(7v-10)+12(-2v+3)

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Solution for 6v-8+11=6(7v-10)+12(-2v+3) equation: 



6v-8+11=6(7v-10)+12(-2v+3)

We move all terms to the left:

6v-8+11-(6(7v-10)+12(-2v+3))=0

We add all the numbers together, and all the variables

6v-(6(7v-10)+12(-2v+3))+3=0



We calculate terms in parentheses: -(6(7v-10)+12(-2v+3)), so:

6(7v-10)+12(-2v+3)

We multiply parentheses

42v-24v-60+36

We add all the numbers together, and all the variables

18v-24

Back to the equation:

-(18v-24)



We get rid of parentheses

6v-18v+24+3=0

We add all the numbers together, and all the variables

-12v+27=0

We move all terms containing v to the left, all other terms to the right

-12v=-27

v=-27/-12

v=2+1/4

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