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6v^2+66v+60=0
a = 6; b = 66; c = +60;
Δ = b2-4ac
Δ = 662-4·6·60
Δ = 2916
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{2916}=54$$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(66)-54}{2*6}=\frac{-120}{12} =-10 $$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(66)+54}{2*6}=\frac{-12}{12} =-1 $
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