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6v^2-6v=36
We move all terms to the left:
6v^2-6v-(36)=0
a = 6; b = -6; c = -36;
Δ = b2-4ac
Δ = -62-4·6·(-36)
Δ = 900
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{900}=30$$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-6)-30}{2*6}=\frac{-24}{12} =-2 $$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-6)+30}{2*6}=\frac{36}{12} =3 $
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