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6w^2+18w=0
a = 6; b = 18; c = 0;
Δ = b2-4ac
Δ = 182-4·6·0
Δ = 324
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{324}=18$$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(18)-18}{2*6}=\frac{-36}{12} =-3 $$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(18)+18}{2*6}=\frac{0}{12} =0 $
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