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6w^2-11w+12=6w
We move all terms to the left:
6w^2-11w+12-(6w)=0
We add all the numbers together, and all the variables
6w^2-17w+12=0
a = 6; b = -17; c = +12;
Δ = b2-4ac
Δ = -172-4·6·12
Δ = 1
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1}=1$$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-17)-1}{2*6}=\frac{16}{12} =1+1/3 $$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-17)+1}{2*6}=\frac{18}{12} =1+1/2 $
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