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6w^2-23+10=0
We add all the numbers together, and all the variables
6w^2-13=0
a = 6; b = 0; c = -13;
Δ = b2-4ac
Δ = 02-4·6·(-13)
Δ = 312
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{312}=\sqrt{4*78}=\sqrt{4}*\sqrt{78}=2\sqrt{78}$$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-2\sqrt{78}}{2*6}=\frac{0-2\sqrt{78}}{12} =-\frac{2\sqrt{78}}{12} =-\frac{\sqrt{78}}{6} $$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+2\sqrt{78}}{2*6}=\frac{0+2\sqrt{78}}{12} =\frac{2\sqrt{78}}{12} =\frac{\sqrt{78}}{6} $
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