6x(-6+4x)=26

Solution for 6x(-6+4x)=26 equation:

6x(-6+4x)=26

We move all terms to the left:

6x(-6+4x)-(26)=0

We add all the numbers together, and all the variables

6x(4x-6)-26=0

We multiply parentheses

24x^2-36x-26=0

a = 24; b = -36; c = -26;
Δ = b2-4ac
Δ = -362-4·24·(-26)
Δ = 3792
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{3792}=\sqrt{16*237}=\sqrt{16}*\sqrt{237}=4\sqrt{237}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-36)-4\sqrt{237}}{2*24}=\frac{36-4\sqrt{237}}{48}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-36)+4\sqrt{237}}{2*24}=\frac{36+4\sqrt{237}}{48}
$