6x(1-3-2)+5(4x-3)=8(X-1)+2x

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Solution for 6x(1-3-2)+5(4x-3)=8(X-1)+2x equation: 



6x(1-3-2)+5(4x-3)=8(x-1)+2x

We move all terms to the left:

6x(1-3-2)+5(4x-3)-(8(x-1)+2x)=0

We add all the numbers together, and all the variables

6x(-4)+5(4x-3)-(8(x-1)+2x)=0

We multiply parentheses

-24x+20x-(8(x-1)+2x)-15=0



We calculate terms in parentheses: -(8(x-1)+2x), so:

8(x-1)+2x

We add all the numbers together, and all the variables

2x+8(x-1)

We multiply parentheses

2x+8x-8

We add all the numbers together, and all the variables

10x-8

Back to the equation:

-(10x-8)



We add all the numbers together, and all the variables

-4x-(10x-8)-15=0

We get rid of parentheses

-4x-10x+8-15=0

We add all the numbers together, and all the variables

-14x-7=0

We move all terms containing x to the left, all other terms to the right

-14x=7

x=7/-14

x=-1/2

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