6x(10x+1)=0

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Solution for 6x(10x+1)=0 equation:



6x(10x+1)=0
We multiply parentheses
60x^2+6x=0
a = 60; b = 6; c = 0;
Δ = b2-4ac
Δ = 62-4·60·0
Δ = 36
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{36}=6$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(6)-6}{2*60}=\frac{-12}{120} =-1/10 $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(6)+6}{2*60}=\frac{0}{120} =0 $

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