6x(10x+2)=0

Solution for 6x(10x+2)=0 equation:

6x(10x+2)=0

We multiply parentheses

60x^2+12x=0

a = 60; b = 12; c = 0;
Δ = b2-4ac
Δ = 122-4·60·0
Δ = 144
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{144}=12$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(12)-12}{2*60}=\frac{-24}{120}
=-1/5
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(12)+12}{2*60}=\frac{0}{120}
=0
$