6x(15+4x)=35

Solution for 6x(15+4x)=35 equation:

6x(15+4x)=35

We move all terms to the left:

6x(15+4x)-(35)=0

We add all the numbers together, and all the variables

6x(4x+15)-35=0

We multiply parentheses

24x^2+90x-35=0

a = 24; b = 90; c = -35;
Δ = b2-4ac
Δ = 902-4·24·(-35)
Δ = 11460
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{11460}=\sqrt{4*2865}=\sqrt{4}*\sqrt{2865}=2\sqrt{2865}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(90)-2\sqrt{2865}}{2*24}=\frac{-90-2\sqrt{2865}}{48}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(90)+2\sqrt{2865}}{2*24}=\frac{-90+2\sqrt{2865}}{48}
$