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6x(2)-16x=6
We move all terms to the left:
6x(2)-16x-(6)=0
We add all the numbers together, and all the variables
6x^2-16x-6=0
a = 6; b = -16; c = -6;
Δ = b2-4ac
Δ = -162-4·6·(-6)
Δ = 400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{400}=20$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-16)-20}{2*6}=\frac{-4}{12} =-1/3 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-16)+20}{2*6}=\frac{36}{12} =3 $
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