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6x(2x+1)=330
We move all terms to the left:
6x(2x+1)-(330)=0
We multiply parentheses
12x^2+6x-330=0
a = 12; b = 6; c = -330;
Δ = b2-4ac
Δ = 62-4·12·(-330)
Δ = 15876
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{15876}=126$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(6)-126}{2*12}=\frac{-132}{24} =-5+1/2 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(6)+126}{2*12}=\frac{120}{24} =5 $
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