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6x(2x+4)=180
We move all terms to the left:
6x(2x+4)-(180)=0
We multiply parentheses
12x^2+24x-180=0
a = 12; b = 24; c = -180;
Δ = b2-4ac
Δ = 242-4·12·(-180)
Δ = 9216
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{9216}=96$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(24)-96}{2*12}=\frac{-120}{24} =-5 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(24)+96}{2*12}=\frac{72}{24} =3 $
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