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6x(2x+6)=5x+20
We move all terms to the left:
6x(2x+6)-(5x+20)=0
We multiply parentheses
12x^2+36x-(5x+20)=0
We get rid of parentheses
12x^2+36x-5x-20=0
We add all the numbers together, and all the variables
12x^2+31x-20=0
a = 12; b = 31; c = -20;
Δ = b2-4ac
Δ = 312-4·12·(-20)
Δ = 1921
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(31)-\sqrt{1921}}{2*12}=\frac{-31-\sqrt{1921}}{24} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(31)+\sqrt{1921}}{2*12}=\frac{-31+\sqrt{1921}}{24} $
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