6x(2x-8)+12=3-3/4x-12-2.5x

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Solution for 6x(2x-8)+12=3-3/4x-12-2.5x equation:



6x(2x-8)+12=3-3/4x-12-2.5x
We move all terms to the left:
6x(2x-8)+12-(3-3/4x-12-2.5x)=0
Domain of the equation: 4x-12-2.5x)!=0
We move all terms containing x to the left, all other terms to the right
4x-2.5x)!=12
x∈R
We add all the numbers together, and all the variables
6x(2x-8)-(-2.5x-3/4x-9)+12=0
We multiply parentheses
12x^2-48x-(-2.5x-3/4x-9)+12=0
We get rid of parentheses
12x^2-48x+2.5x+3/4x+9+12=0
We multiply all the terms by the denominator
12x^2*4x-48x*4x+(2.5x)*4x+9*4x+12*4x+3=0
We add all the numbers together, and all the variables
12x^2*4x-48x*4x+(+2.5x)*4x+9*4x+12*4x+3=0
We multiply parentheses
12x^2*4x+8x^2-48x*4x+9*4x+12*4x+3=0
Wy multiply elements
48x^3+8x^2-192x^2+36x+48x+3=0
We do not support expression: x^3

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